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The Monty Hall Problem (math riddle)
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2019-03-31 at 2:44 PM UTCThe Monty Hall Problem gets its name from the TV game show, Let's Make A Deal (which is hosted by Monty Hall 1). The scenario is such: you are given the opportunity to select one closed door of three, behind one of which there is a prize. The other two doors hide “goats” (or some other such “non-prize”), or nothing at all. Once you have made your selection, Monty Hall will open one of the remaining doors, revealing that it does not contain the prize 2. He then asks you if you would like to switch your selection to the other unopened door, or stay with your original choice. Here is the problem:
Does it matter if you switch?
PS -- I told you I'd make an account, Lanny. -
2019-03-31 at 2:55 PM UTC
Originally posted by yabbadabbadindunuthin The Monty Hall Problem gets its name from the TV game show, Let's Make A Deal (which is hosted by Monty Hall 1). The scenario is such: you are given the opportunity to select one closed door of three, behind one of which there is a prize. The other two doors hide “goats” (or some other such “non-prize”), or nothing at all. Once you have made your selection, Monty Hall will open one of the remaining doors, revealing that it does not contain the prize 2. He then asks you if you would like to switch your selection to the other unopened door, or stay with your original choice. Here is the problem:
Does it matter if you switch?
PS – I told you I'd make an account, Lanny.
Does it matter? If you don't have the prize it matters because you could have it. If you do have the prize it matters because you could trade it for nothing.
I don't understand what you're asking. It doesn't matter mathematically and doesn't increase or decrease your odds, just the end result -
2019-03-31 at 2:56 PM UTCNo math on Sunday
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2019-03-31 at 3:03 PM UTC
Originally posted by Sudo Does it matter? If you don't have the prize it matters because you could have it. If you do have the prize it matters because you could trade it for nothing.
I don't understand what you're asking. It doesn't matter mathematically and doesn't increase or decrease your odds, just the end result
This is what most people's immediate impression is, but that's actually incorrect. You increase your odds of winning by switching. -
2019-03-31 at 4:16 PM UTC
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2019-03-31 at 4:19 PM UTCthis is gonna be good..
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2019-03-31 at 4:32 PM UTCYes it matters. Switching gives you 2/3 chance of success.
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2019-03-31 at 5:57 PM UTCTwo of the three doors hold valuable prizes, one prize more valuable than the other. The third door holds the booby prize. So even if you choose a door and win one prize, one of the remaining two doors may hold an even more valuable prize, but you could get stuck with the booby prize, instead of the prize you have already won. Do you understand now?
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2019-03-31 at 6:08 PM UTC
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2019-03-31 at 6:13 PM UTClol
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2019-03-31 at 6:16 PM UTC
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2019-03-31 at 7 PM UTCWHO ARE YOU? ARE YOU HE? GHEYCROW IS ME.
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2019-03-31 at 7:03 PM UTCCounter-intuitively, due to some mathematical mumbo jumbo, allegedly it's better to switch in this case. It should, by all rights, be 50/50 odds on either door. But it's not. Because math.
Fuck math. -
2019-03-31 at 7:21 PM UTC
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2019-03-31 at 8:30 PM UTCniggerThe following users say it would be alright if the author of this post didn't die in a fire!
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2019-03-31 at 8:34 PM UTC
Originally posted by whoami You double the odds of winning from 1/3 to 2/3 by switching. Most people get this wrong because they treat it as a standard probability problem and don't account for the fact that Monty Hall knows which door has the prize behind it and isn't opening them at random.
Right, which just means that you can be sure that either the door you have selected or the door remaining has the prize. 50/50. Math is retarded. Fuck math. -
2019-03-31 at 8:35 PM UTCITT freshman year in community college math classThe following users say it would be alright if the author of this post didn't die in a fire!
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2019-03-31 at 8:39 PM UTC
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2019-03-31 at 8:42 PM UTC
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2019-03-31 at 8:50 PM UTCnigger
